IP ADDRESS CALCULATION

The calculation of IP address

The IP address that had been given for UTeM is 192.168.0.0/16 and we need to divide into 30 department. As for the netmask for this IP address is /16.

/ 16 = 11111111.11111111.00000000.00000000

To find the value of available IP address in the /16 by calculate the value of zero and make it as the value of power for based 2.

216 = 65,536   65,536 – 2 (for gateway and broadcast IP) = 65,534

The way we divide the available IP according to the department by division:-

     

65.534/30 = 2184.48

So approximately 2184 IP are available for every department. Then we need to find the value of subnet that contain more than 2000 available IP address but not more than 3000.

 

211 = 2048           = 11111111.11111111.11111000.00000000           = /21

Then, we have to find the 11^th subnet for the IT center.

1-      192.168.0.0 – 192.168.7.255 2-      192.168.8.0 – 192.168.15.255 3-      192.168.16.0 – 192.168.23.255 4-      192.168.24.0 – 192.168.31.255 5-      192.168.32.0 – 192.168.39.255 6-      192.168.40.0 – 192.168.47.255 7-      192.168.48.0 – 192.168.55.255 8-      192.168.56.0 – 192.168.63.255 9-      192.168.64.0 – 192.168.71.255 10-  192.168.72.0 – 192.168.79.255 11-  192.168.80.0 – 192.168.87.255

From the IP address that we got, we need to find the 3^rd IP address for the Ulearn System server. As we all know two IP address that we need to reserve as for the first one is for the gateway IP while for the other one is for the broadcast IP.

Network = 192.168.80.0/21      Broadcast = 192.168.87.255      Gateway = 192.168.80.1      3rd available IP address is = 192.168.80.4

Finally, we will assign the IP address according to the calculation above.